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9y^2-22y-15=0
a = 9; b = -22; c = -15;
Δ = b2-4ac
Δ = -222-4·9·(-15)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-32}{2*9}=\frac{-10}{18} =-5/9 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+32}{2*9}=\frac{54}{18} =3 $
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